Multiple Catch Blocks Example in Java
Introduction
Multiple Catch Blocks is a classic Java console program that demonstrates the concept with complete source code and sample output. Exceptions represent runtime errors; Java uses try-catch-finally to handle them safely.
This tutorial walks through the program line by line, explains how the logic works, and highlights best practices you can apply in your own code.
Syntax
try {
// Do something
} catch (Exception1 ex) {
// Do something with caught exception
} catch (Exception2 ex) {
// Do something with caught exception
}Multiple Catch Blocks Example Program
public class MultipleCatchBlocks {
public static void main(String args[]){
Scanner scanner = new Scanner(System.in);
System.out.println("Enter the divisor to divide 100 : ");
int divisor = scanner.nextInt();
try{
int[] array=new int[10];
int result = 100/divisor;
array[10]=result;
}catch(ArithmeticException e){
System.out.println("Arithmetic exception has occurred");
}catch(ArrayIndexOutOfBoundsException e){
System.out.println("Array Index Out Of Bounds Exception has occurred");
}catch(Exception e){
System.out.println("Common exception has occurred");
}
}
}Sample Output
Enter the divisor to divide 100 :
0
Arithmetic exception has occurredWhen to use
Use this multiple catch blocks example when learning or revising core Java syntax.
How it works
-
Execution begins in the
mainmethod — the JVM calls this method when you run the class. -
A
Scannerreads typed input from the keyboard (System.in). -
A
println/printcall writes text to the console — part of the sample output below. -
int divisor = scanner.nextInt();updates a variable used in the calculation or output. -
int[] array=new int[10];updates a variable used in the calculation or output. -
int result = 100/divisor;updates a variable used in the calculation or output. -
array[10]=result;updates a variable used in the calculation or output. -
A
println/printcall writes text to the console — part of the sample output below.